What are the first three terms of the sequence defined by the following function? f(n)=41+(n-1)^5

asked May 25, 2022 62.6k views

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What are the first three terms of the sequence defined by the following function?

f(n)=41+(n-1)^5

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Answer:

Explanation:

$f(n)=41+(n-1)^5\\\\f(1)=41+(1-1)^5=41\\\\f(2)=41+(2-1)^5=41-1=40\\\\f(3)=41+(3-1)^5=41-32=9$

Nadimibox answered May 30, 2022

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