62.6k views
2 votes
What are the first three terms of the sequence defined by the following function?

f(n)=41+(n-1)^5

User Xilconic
by
7.9k points

1 Answer

5 votes

Answer:

41, 40 and 9

Explanation:


f(n)=41+(n-1)^5\\\\f(1)=41+(1-1)^5=41\\\\f(2)=41+(2-1)^5=41-1=40\\\\f(3)=41+(3-1)^5=41-32=9

User Nadimibox
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories