Question

I’ll give you fat points

Answer 1

`\\ \sf\longmapsto (x-1)(x+2)(x+3)`

`\\ \sf\longmapsto (x-1)\left\{(x+2)(x+3)\right\}`

`\\ \sf\longmapsto (x-1)(x^2+5x+6)`

`\\ \sf\longmapsto x(x^2+5x+6)-1(x^2+5x+6)`

`\\ \sf\longmapsto x^3+5x^2+6x-x^2-5x-6`

`\\ \sf\longmapsto x^3+4x^2+x-6`

• a=1
• b=4
• c=1
• d=-6

Answer 2

• See below

Explanation:

Multiply and simplify:

• (x - 1)(x + 2)(x + 3) =
• (x² + 2x - x -2)(x + 3) =
• (x² + x - 2)(x + 3) =
• x³ + 3x² + x² + 3x - 2x - 6 =
• x³ + 4x² + x - 6

From the final polynomial we can see that:

• a = 1, b = 4, c = 1 and d = - 6

So all the coefficients are positive but the constant d is negative