Answer:
S₁₀=620
Explanation:
This is an arithmetic sequence with a common difference of d=12
The formula for an arithmetic series is Sₙ=(n/2)(a₁+aₙ) where aₙ is the nth term and a₁ is the first term.
We know that a₁=8 and d=12 where the 10th term would be a₁₀=8+(10-1)12=116.
Therefore, the sum of the first 10 terms of the arithmetic series is S₁₀=(10/2)(8+116)=(5)(124)=620