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What is the initial value of h(t)= -9.8t2+48t+50?
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What is the initial value of h(t)= -9.8t2+48t+50?

What is the initial value of h(t)= -9.8t2+48t+50?-example-1
User Kmikael
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4 votes
48 is the correct answer
User Timofey
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4 votes

Answer:


h(t) = 9.8 {t}^(2) + 48t + 50 \\ initially : \: t = 0 \\ h(0) = 50

User Xavier Delaruelle
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