Question

Let R be the triangular region in the first quadrant with vertices at.Points (0,0), (h,0), and (h,r), where r and h are positive constants

Answer 1

The answer is "
`\pi \int^(h)_(0)((r)/(h) x)^2 \ dx`"

Explanation:

`dv=(Area) \ thickness`

`=\pi r^2 \ dx\\\\=\pi ((r)/(h) x)^2 \ dx`

`V= \int^(h)_(0) \pi ((r)/(h) x)^2 \ dx\\\\`

`=\pi \int^(h)_(0)((r)/(h) x)^2 \ dx`