Answer:
The acceleration is:
![4m/s^2](https://img.qammunity.org/2022/formulas/chemistry/high-school/kccyiejqopjw0d73dxawytoliqp86q7c30.png)
Step-by-step explanation:
Given
--- The initial velocity
--- time
-- The final velocity
Required
Determine the acceleration
To do this, we make use of the first equation of motion
![v = u - at](https://img.qammunity.org/2022/formulas/chemistry/high-school/owojn0z6by7osilnko1t1x7cwr6m0n124h.png)
We used negative because the car was coming to stop.
This gives:
![0 = 30 - 7.5 * a](https://img.qammunity.org/2022/formulas/chemistry/high-school/4flldjdcunji6xhuo2ynpq5sitncpyzktb.png)
![0 = 30 - 7.5a](https://img.qammunity.org/2022/formulas/chemistry/high-school/de1oc5tzjbnwawvicaulegnhmx4b4tk833.png)
Collect like terms
![7.5a = 30](https://img.qammunity.org/2022/formulas/chemistry/high-school/csd38u8398e3r1t30edprhx7br4fhbf9u4.png)
Solve for a
![a = (30)/(7.5)](https://img.qammunity.org/2022/formulas/chemistry/high-school/2ttb7lj18xutphqo2itkij2jiywavq1vb2.png)
![a = 4m/s^2](https://img.qammunity.org/2022/formulas/physics/college/5undftcjwyo34iid5d8a2rheqjd8s1si77.png)