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23 votes
23 votes
Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 60km\h slower than the other. If the two planes are 7304 kilometers apart after 4 hours, what is the rate of each plane?

User Joe Audette
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1 Answer

14 votes
14 votes

Answer:

4 V + 4 (V - 60) = D where D is distance apart after 4 hrs

8 V - 240 = 7304

V = 943 km/hr

and V2 = 943 - 60 = 883 km/hr where second plane is 60 km/hr slower

User MSepehr
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