Answer:
(i) In triangle RTO and QSR
Given,
⇒∠RTO=∠OSR=90
o
(QS⊥PR and RT⊥PQ)
⇒QS=RT
⇒QR=RO ....Hypotenuse
∴△RTQ≅△QSR ....RHS criterion
(ii) By using part(1) of a solution, we get
∠TQR=∠SRQ ....By C.P.C.T
⇒∠PQR=∠PRQ
Explanation:
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