Question

A forward horizontal force of 12n is used to pull a crate across a horizontal floor at a constant velocity. If the crate weighs 240n, what is the coefficient of friction?.

Answer 1

Step-by-step explanation:

μ = coefficient of friction.

F = Frictional force = 12N

R = Normal reaction = mg = Weight = 240N

m = mass

g = acceleration due to gravity ≈ 9.8ms—²

μ = F/R

μ = 12/240

μ = ¹/20

μ = 0.05