15.4k views
11 votes
I’m not to sure how I would create a polynomial function from the graph any help or examples meeting the criteria?

I’m not to sure how I would create a polynomial function from the graph any help or-example-1
User JamahalSOF
by
7.4k points

1 Answer

6 votes

Answer:

f(x) = 1/8(x +4)^2(x +1)(x -3)

Explanation:

The end behavior shows both ends of the graph headed to +∞. That means ...

  • the function is of even degree
  • the leading coefficient is positive

There are zeros at x=-4, -1, 3. The graph does not cross the x-axis at x=-4, so that zero has even degree. The smallest degree that will satisfy the degree requirements is 4, where the zero at x=-4 is of multiplicity 2.

__

You know that zero x=p means (x-p) is a factor. The multiplicity is the exponent of the factor, so the factored function so far is ...

f(x) = (1/a)(x +4)^2(x +1)(x -3)

When x=0, this is ...

f(0) = 1/a(4^2)(1)(-3) = -48/a

The graph shows you the y-intercept is -6, so ...

-6 = -48/a

a = 8

The factored polynomial is ...


f(x)=(1)/(8)(x+4)^2(x+1)(x-3)

User Ixodid
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories