Question

F (x) = 2 (x + 1)^2 - 1

Answer 1

Equation: y = x²

• (-2, 4)
• (0, 0)
• (2, 4)

Equation: f(x) = 2(x + 1)² - 1

• (-2, 1)
• (0, 1)
• (2, 17)

Explanation:

Equation: y = x²

• when x = -2, y = (-2)² = 4 ⇒ (-2, 4)
• when x = 0, y = (0)² = 0 ⇒ (0, 0)
• when x = 2, y = (2)² = 4 ⇒ (2, 4)

Equation: f(x) = 2(x + 1)² - 1

f(-2) = 2(-2 + 1)² - 1

= 2(-1)² - 1

=2(1) - 1

= 1

Therefore, (-2, 1)

f(0) = 2(0 + 1)² - 1

= 2(1)² - 1

=2(1) - 1

= 1

Therefore, (0, 1)

f(2) = 2(2 + 1)² - 1

= 2(3)² - 1

=2(9) - 1

= 17

Therefore, (2, 17)