Question

Un diapasón vibra a 140 [Hz] y la onda emitida por él se propaga con una rapidez de 340 m/s.Considerando lo anterior, se puede afirmar correctamente que la longitud de onda de la onda emitida por el diapasón es

Answer 1

The question is: A tuning fork vibrates at 140 [Hz] and the wave emitted by it propagates with a speed of 340 m / s. Considering the above, it can be correctly stated that the wavelength of the wave emitted by the tuning fork is

Answer: Wavelength of the wave emitted by the tuning fork is 2.43 m.

Step-by-step explanation:

Given: Frequency = 140 Hz

Speed = 340 m/s

wavelength = ?

Formula used to calculate the wavelength is as follows.

`\lambda = (v)/(f)`

where,

`\lambda` = wavelength

v = speed

f = frequency

Substitute the values into above formula.

`\lambda = (v)/(f)\\= (340 m/s)/(140 Hz) (1 Hz = 1 s^(-1))\\= 2.43 m`

Thus, we can conclude that wavelength of the wave emitted by the tuning fork is 2.43 m.