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What is the surface area of the net? *inches squared*

What is the surface area of the net? *inches squared*-example-1

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9514 1404 393

Answer:

75 in^2

Explanation:

The central vertical rectangle (including "ears") has dimensions

3 in wide by (9+2+2) = 13 in tall

Its area is

A = LW = (3 in)(13 in) = 39 in^2

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The two rectangles either side of that have dimensions 2 in by 9 in. The area of each of them is

A = LW = (2 in)(9 in) = 18 in^2

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The total net area is the sum of the areas of the parts:

left rectangle + central rectangle + right rectangle

= 18 in^2 + 39 in^2 + 18 in^2 = 75 in^2 . . . . surface area of the net

User Jeffrey Froman
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