Answer:
The pvalue of the test is 0.0083 < 0.1, which means that there is enough evidence to conclude that residents of Legacy Ranch use less water on average
Explanation:
The American Water Works Association reports that the per capita water use in a single-family home is 69 gallons per day. Test that the residents use less water.
At the null hypothesis, we test that the mean is 69, that is:

At the alternate hypothesis, we test that the mean is less than 69, that is:

The test statistic is:
As we have the standard deviation for the sample, we use the t-statistic.

In which X is the sample mean,
is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.
69 is tested at the null hypothesis:
This means that

Thirty-six owners responded, and the sample mean water use per day was 64 gallons with a standard deviation of 8.8 gallons per day.
This means that

Value of the test statistic:



Pvalue of the test and decision:
The pvalue of the test is the probability of finding a mean less than 64, which is the pvalue of t = -3.41, found on the t-table with 36 - 1 = 35 degrees of freedom on a one-tailed test.
With calculator help, the pvalue is 0.0083.
The pvalue of the test is 0.0083 < 0.1, which means that there is enough evidence to conclude that residents of Legacy Ranch use less water on average