Question

-. How many moles of Pb are contained in 2.49 x 1025 atoms Pb?

Answer 1

Answer: There are
`4.13 * 10^(-3)` moles of Pb are contained in
`2.49 * 10^(25)` atoms Pb.

Step-by-step explanation:

According to the mole concept, 1 mole of every substance contains
`6.023 * 10^(23)` atoms.

Hence, number of moles present in
`2.49 * 10^(25)` atoms of Pb are as follows.

`No. of moles = (2.49 * 10^(25))/(6.023 * 10^(23))\\= 4.13 * 10^(-3) mol`

Thus, we can conclude that there are
`4.13 * 10^(-3)` moles of Pb are contained in
`2.49 * 10^(25)` atoms Pb.