Question

Simple geometry question please help :)

Answer 1

volume of the composite figure = volume of cylinder - volume of cone

volume of cylinder = πr²h

`(22)/(7) * 8 * 8 * 12 \\ \\ = > (16896)/(7) \: ft {}^(3)`

volume of cone = 1/3 πr²h

`(1)/(3) * (22)/(7) * 8 * 8 * 12 \\ \\ = > (16896)/(21) \: ft {}^(3)`

`total \: volume = (16896)/(7) - (16896)/(21) \\ \\ = > (50688 - 16896)/(21) \\ \\ = > (33792)/(21) \\ \\ = > 1609.14 \: ft {}^(3) (approx.)`

hope helpful~

Answer 2

`\large\boxed{\sf\: Volume \: of \: the \: figure\: \approx \: 1607.68\: feet^(3)}`

Explanation:

We need to find the volume of each composite figure given in the question. Here, the figures are ⟶ a cylinder & a cone.

Given,

• Radius (r) = 8 feet
• Height (h) = 12 feet
• Take the value of π = 3.14

NOTE: The values of the radius & the height of both the figures remain the same as the cone is fit inside the cylinder.

The formulae of the volume of the figures are
`\downarrow`

• Cylinder = πr²h
• Cone = ⅓ πr²h

So,

Volume of cylinder

= πr²h

= 3.14 × (8)² × 12

= 2,411.52 feet³ (approx.)

Volume of cone

= ⅓ πr²h

= ⅓ × Volume of cylinder

= ⅓ × 2,411.52

= 803.84 feet³ (approx.)

Thus, the total volume of the figure

= Volume of cylinder - Volume of the cone

= 2,411.52 - 803.84

= 1,607.68 feet³ (approx.)

•°• Total volume of the composite figure = 1,607.68 feet³ (approx)

_______________

Hope this helps!