Question

Solve the quadratic linear below :
6x²-x-2=0​

Answer 1

x = 3/2; x = -1/2

Explanation:

6x² - x - 2 = 0

⇔ 6x² - 4x + 3x - 2 = 0

⇔ (6x² - 4x) + (3x - 2) = 0

⇔ 2x(3x - 2) + (3x - 2) = 0

⇔ (3x - 2)(2x + 1) = 0

⇔
`\left \{ {{3x - 2=0} \atop {2x + 1=0}} \right.`

⇔
`\left \{ {{3x=2} \atop {2x=-1}} \right.`

⇔
`\left \{ {{x=2/3} \atop {x=-1/2}} \right.`