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Given the [H+] = 3.89x10^-7M, what is the [OH-]?

Given the [H+] = 3.89x10^-7M, what is the [OH-]?
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Given the [H+] = 3.89x10^-7M, what is the [OH-]?

Given the [H+] = 3.89x10^-7M, what is the [OH-]?-example-1
User David Siegel
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1 Answer

7 votes

Answer:

[H][OH] = 10^-7

[OH] = 10^-7/ 3.89x10^-7 = 0.257M

User IqqmuT
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