Question

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2)

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Answer 1

make x→0

`p(0)=(0)^(2)-3(0)+2`

→
`p(0)=0+0+2`

→
`p(0)=2`

`------`

Replace x→-1

`p(-1)=(-1) ^(2) -3 (-1)+2`

→
`p(-1)=1-3+2`

→
`p(-1)=0`

`----------`

Now make x→2

`p(2)=(2) ^(2) -3(2)+2`

→
`p(2)=4-6+2`

→
`p(2)=0`

`Answer:-2,0,0`

`-----------`

hope it helps...

have a great day!!