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21 votes
21 votes
Line c has an equation of y = 4x + 9. Line dis parallel to line c and passes through (-4,-4).

What is the equation of line d?
Write the equation in slope-intercept form. Write the numbers in the equation as simplified
proper fractions, improper fractions, or integers.

User Siddhpura Amit
by
2.8k points

1 Answer

20 votes
20 votes

Answer:


\large\boxed{\sf y = 5x +16}

Explanation:

Here it is given that a line c has a equation of ,


\sf\qquad\longrightarrow y = 4x + 9

And there is another line d which is parallel to line c and passes through the point (-4,-4) . And we need to find out the equation of the line .

Firstly we know that the slope of two parallel lines is same . So on comparing the given line to the slope intercept form of the line which is y = mx + c , we have ;


\sf\qquad\longrightarrow m = 4

Therefore the slope of the parallel line will be ,


\sf\qquad\longrightarrow m_(||)= 4

On using the point slope form of the line , we have ;


\sf\qquad\longrightarrow y - y_1 = m(x-x_1)\\

Substitute the values ,


\sf\qquad\longrightarrow y - (-4) = 5\{ x -(-4)\}

Simplify ,


\sf\qquad\longrightarrow y +4 = 5(x +4)

Open the brackets ,


\sf\qquad\longrightarrow y + 4 = 5x + 20

Subtract 4/on both sides ,


\sf\qquad\longrightarrow y = 5x +20-4

Simplify ,


\sf\qquad\longrightarrow \pink{ y = 5x + 16}

Hence the equation of the line is y = 5x + 16

User Gmemon
by
3.0k points