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What is the minimum or maximum value of the equation of this equation?
f(x) = -(x-8)^2 -30​

User Mariarita
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1 Answer

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Answer:

f(8) = -30 is the maximum

Explanation:

The equation is that of a parabola in vertex form:

y = a(x -h)^2 +k . . . . . . . . (h, k) is the vertex; 'a' is the scale factor

Comparing this form to the given equation, we have ...

f(x) = -(x -8)^2 -30

  • a = -1
  • h = 8
  • k = -30

That is, the scale factor is -1, and the vertex is (8, -30).

When the scale factor is negative, the graph opens downward and the vertex is a maximum. The maximum value is -30.

What is the minimum or maximum value of the equation of this equation? f(x) = -(x-example-1
User Pedro Yan Ornelas
by
7.5k points

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