Question

A mosquito is flying at a speed of 0.5 m/sec. When it sees a person, the mosquito speeds up to a speed of 2 meters per

second in 0.25 seconds. What is the acceleration of the mosquito?

Write the equation(.5 pts)

Fill in the equation( .5 pts)

Give your numerical answer(.5 pts) with units(.5 pts)

Answer 1

`a=6\ m/s^2`

Step-by-step explanation:

Given that,

Initial speed, u = 0.5 m/s

Final speed, v = 2 m/s

Time, t = 0.25 s

Let a be the acceleration of the mosquito. Using first equation of motion as follows :

v=u+at

Put all the values,

2=0.5+0.25a

So,

`a=(2-0.5)/(0.25)\\\\a=6\ m/s^2`

So, the acceleration of the mosquito is equal to
`6\ m/s^2`.