Answer:
New volume = 18.33 L
Step-by-step explanation:
Given that,
Initial temperature,
![T_1=0^(\circ) C=273.15\ K](https://img.qammunity.org/2022/formulas/chemistry/college/kfuzsjq45uvckpxis3dmz8nictv16a855c.png)
Initial volume,
![V_1=20\ L](https://img.qammunity.org/2022/formulas/chemistry/college/9siws8ahrbdin6hc0jeggmdz6sdcrr9xsu.png)
Final temperature,
![T_2=-22.8^(\circ)C=250.35\ K](https://img.qammunity.org/2022/formulas/chemistry/college/k2jqncpbwpoff6td0dnp8v4rsm7picq5fv.png)
We need to find the final volume when pressure is held constant. The relation between volume and temperature is given by :
![V\propto T\\\\(V_1)/(V_2)=(T_1)/(T_2)\\\\V_2=(V_1T_2)/(T_1)\\\\V_2=(20* 250.35)/(273.15)\\\\V_2=18.33\ L](https://img.qammunity.org/2022/formulas/chemistry/college/xml8yo0ijuk0c68v67alr2g6mlsft9csd0.png)
So, the new volume is equal to
.