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Geometry - No links please

Geometry - No links please-example-1
User Lonesome
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1 Answer

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Answer:

36

Explanation:


In\: \triangle ABR \:\&\: \triangle ANH

BR || HN(Given)

Therefore,


\angle ABR \cong \angle ANH (Alternate angles)


\angle BAR \cong \angle HAN (Vertical angles)


\therefore \triangle ABR \sim \triangle ANH (AA postulate)


\therefore (AB)/(AN) =(BR)/(HN) (csst)


\therefore (x)/(16) =(27)/(12)


\therefore (x)/(16) =(9)/(4)


\therefore x =(9* 16)/(4)


\therefore x ={9* 4}


\therefore x =36

User Deeps
by
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