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Find the value of x.

Find the value of x.-example-1
User Rhynden
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1 Answer

4 votes

Answer:


\boxed {\boxed {\sf x=28}}

Explanation:

This is a right triangle. The small square in the corner represents a 90 degree angle. We can use trigonometry. The three major ratios are:

  • sin(θ)=opposite/hypotenuse
  • cos(θ)=adjacent/hypotenuse
  • tan(θ)= opposite/adjacent

The angle, or θ, is 60 degrees. The side measuring 14 is adjacent to this angle. x is the hypotenuse because it is opposite the right angle. Since we have the adjacent side and the hypotenuse, we use cosine.


cos (\theta) = \frac {adjacent}{hypotenuse}


cos(60)= (14)/(x)

Since we are solving x, we must isolate the variable. First, cross multiply.


\frac {cos(60)}{1}= (14)/(x)

Multiply the first numerator (cos60) by the second denominator (x).

Then, multiply the first denominator (1) by the second numerator (14)


cos (60)*x= 14*1


cos(60)*x= 14

The cosine of 60 is equal to 1/2,


(1)/(2) x= 14

x is being multiplied by 1/2. The inverse of multiplication is division. Divide both sides of the equation by 1/2. Since this is a fraction, you can also multiply by the reciprocal: 2.


2* (1)/(2) x= 14 *2


x=14 *2\\ x=28

The hypotenuse, x, is equal to 28.

User Paul Batum
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6.0k points