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5 votes
The value -1 is a solution for x2 - 6x+ 5 = 0.
True or false

User FreddieH
by
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1 Answer

4 votes

Answer:

false

Explanation:

  • If -1 us a solution then putting -1 in place of x will be 0


\rm \dashrightarrow \: {x}^(2) - 6x + 5 = 0 \\ \rm \dashrightarrow \: {( - 1)}^(2) - 6( - 1) + 5 = 0 \\ \rm \dashrightarrow \: 1 + 6 + 5 = 0 \\ \rm \dashrightarrow \: 7 + 5 = 0 \\ \rm \dashrightarrow \: 12 \cancel{ = }0

User Csteifel
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