Question

1

What is the solution to the equation n-5
2 16
*+5 12 - 25?
Oh=
11
3
Oh=5
O h=7
21
Oh=
2

Answer 1

`\begin{aligned}(1)/(h-5)+(2)/(h+5)&=(16)/(h^2-25)\\((h+5)+2(h-5))/((h-5)(h+5))&=(16)/(h^2-25)\\(h+2h+5-10)/(h^2-25)&=(16)/(h^2-25)\\\frac{3h-5}{\cancel{h^2-25}}&=\frac{16}{\cancel{h^2-25}}\\3h-5&=16\\3h&=16+5\\3h&=21\\h&=(21)/(3)\\h&=7\end{aligned}`