Question

Please help me please I reallly need help

Answer 1

we have:

`v = (1)/(3) \pi \: r {}^(2)h \\ \\ = > 60\pi = (1)/(3) \pi \: r {}^(2) h \\ \\ < = > 180 = r {}^(2) h`

=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15

=> only r²h = 5.36 satisfy the problem

=> h = 5

h = 5 r = 6

h = 5 r = 6=> d = 12