Question

An object moving initially with a velocity of 12m/s is uniformly accelerated at rate of 3 m/s^2. What is its velocity after 8 seconds acceleration? If it started at position 8 m. What is its position after 8s?

Answer 1

36 m/s is v2

Step-by-step explanation:

formula is v2 = v1+ (a)(t)

v2 is unknown so that stays as the variable, v1 = 12 a = 3 t = 8

so the equation would be

v2 = 12 + 3x8

v2 = 12 + 24

v2 = 36

hope this helps!