Answer:
Department B's cost allocated to Department C = $14,021
Step-by-step explanation:
Let A and B represents the total costs of Departments A and B repectively. We therefore have:
A = 80,000 + 0.3B ……………………. (1)
B = 60,000 + 0.1A ………………...... (2)
Substituting equation (1) into (2) and solve for B, we have:
B = 60,000 + 0.1(80,000 + B0.3)
B = 60,000 + 8,000 + 0.03B
B - 0.03B = 68,000
0.97B = 68,000
B = 68,000 / 0.97
B = 70,103
This implies that the total cost of B is $70,103.
Therefore, we have:
Department B's cost allocated to Department C = B * Proportion of service by B to C = $70,103 * 20% = $14,021