Correct question:
Imagine that a 1200 kg vehicle speeds up from rest to 20.0 m/s in 80 s.
How much work was done on the car? (Answer in 3 sig figs)
Answer:
the work done on the vehicle is 2.40 x 10⁵ J
Step-by-step explanation:
Given;
mass of the vehicle, m = 1200 kg
initial velocity of the vehicle, u = 0
final velocity of the vehicle, v = 20 m/s
time of motion of the vehicle, t = 80 s
The distance moved by the vehicle is calculated as;
![s = ((v + u)/(2) )t\\\\s = ((20+ 0)/(2) )(80)\\\\s = 800 \ m](https://img.qammunity.org/2022/formulas/physics/high-school/6q0ln5pgfrk1zmopfhz4kewat53ytjq99w.png)
The force applied to the vehicle is calculated as;
![F = ma = (m v)/(t) = (1200 * 20)/(80) = 300 \ N\\\\](https://img.qammunity.org/2022/formulas/physics/high-school/bsuq5dzuyz77xe70hlx3ic06f3aa5yea00.png)
The work done on the vehicle is calculated as;
W = F x d
W = 300 x 800
W = 2.4 x 10⁵ J.
Therefore, the work done on the vehicle is 2.40 x 10⁵ J