Question

The Hershey Company has been receiving complaints that their chocolate almond bars contain fewer almonds than they've previously contained. Hershey's records show that over time each bar of candy contains a mean of 17 almonds. A sample of 30 of last month's chocolate bars has a mean of 14 almonds with a standard deviation of 8. Test the hypothesis (alpha

Answer 1

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State appropriate Hypothesis for performing a significance test. Be sure to define the parameter of interest. (u = mu)

`H_(null):u=17 \\H_(a):u<17` Where mu = the true mean of almonds in each bar of candy.

Calculate the test statistic and the P-Value.

mu = 17

x-bar = 14

`S_(x) = 8`

`n = 30`

Use the T-Test (STAT) if you have a Graphing Calculator.

Interpret the P-Value in context.

Assuming the mean number of almonds in each candy bar is 17, there is a [P-Value] probability of getting a sample mean of 14 by chance alone.

What is the decision at the given significance level?

P-val of [P-Value] is (> or <?) to the alpha level [
`a`], so you must (fail to reject or reject?) the Null Hypothesis.

What do you conclude? (If P-val is smaller than the alpha level, reject the null hypothesis, meaning there is significant evidence.)

Because the P-Value of [P-Value] is (less/greater) than
`a = (?)`, the observed result (is or is not?) statistically significant. There (is or is not?) significant evidence to conclude that the chocolate almond bars contain fewer almonds than they've previously contained.