Question

How efficient is a pulley system if it enables you to lift a 600.0 Newton engine 0.600 meters if you exerted 35.7 Newtons of force while pulling 11.43 meters of rope?

Answer 1

η = 0.882 = 88.2 %

Step-by-step explanation:

The efficiency of the pulley system can be given as follows:

`\eta = (W_(out))/(W_(In))\\\\`

where,

η = efficiency of pulley system = ?

W_out = Output Work = (600 N)(0.6 m) = 360 J

W_in = Input Work = (35.7 N)(11.43 m) = 408.051 J

Therefore,

`\eta = (360\ J)/(408.051\ J)`

η = 0.882 = 88.2 %