Question

I need solution to these two questions please

Answer 1

Explanation:

4). Given functions are,

`f(x)=(1)/(3x)`

For
`x=(1)/(12)`

`f((1)/(12))=(1)/(3((1)/(12)))`

`=(1)/((1)/(4))`

`=1*(4)/(1)`

`=4`

`g(x)=(1)/(x^2)`

For
`x=(1)/(5)`,

`g((1)/(5))=(1)/(((1)/(5))^2)`

`=(1)/((1)/(25))`

`=25`

`f((1)/(12))-g((1)/(5))=4-25`

`=-21`

5). f(x) = -2x² + 3x - 8

f(k + 4) = -2(k + 4)² + 3(k + 4) - 8

= -2(k² + 8k + 16) + 3(k + 4) - 8

= -2k² - 16k - 32 + 3k + 12 - 8

= -2k² - 13k - 28