Question

1. If you have 200 g of Al2(CO3)3 , how many moles will you have? Show your work.

Answer 1

Answer: There are 0.854 moles of
`Al_(2)(CO_(3))_(3)` present in 200 g of
`Al_(2)(CO_(3))_(3)`.

Step-by-step explanation:

Given: Mass of
`Al_(2)(CO_(3))_(3)` = 200 g

As number of moles is the mass of substance divided by its molar mass.

Molar mass of
`Al_(2)(CO_(3))_(3)` is 233.99 g/mol.

Therefore, moles of
`Al_(2)(CO_(3))_(3)` is calculated as follows.

`No. of moles = (mass)/(molar mass)\\= (200 g)/(233.99 g/mol)\\= 0.854 mol`

Thus, we can conclude that there are 0.854 moles of
`Al_(2)(CO_(3))_(3)` present in 200 g of
`Al_(2)(CO_(3))_(3)`.