Question

A train is travelling at a speed

of 90 km h-¹. Brakes are applied
so as to produce a uniform
acceleration of - 0.5 m s-². Find
how far the train will go before it
is brought to rest.​

Answer 1

Step-by-step explanation:

`speed :`

`speed : U = ((90 * 1000) \: m)/((1 * 3600) \: s) \\ = 25 \: m {s}^( - 1) \\ from \: third \: equation \\ {V}^(2) = {U}^(2) + 2aS \\ 0 = {25}^(2) * (2 * - 0.5 * S) \\ 625 = S \\ S = 625 \: m`