In ΔIJK, j = 770 cm, ∠I=88° and ∠J=15°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.

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asked Nov 10, 2022 56.1k views

2 votes

In ΔIJK, j = 770 cm, ∠I=88° and ∠J=15°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.

Mathematics
high-school

Ulatekh asked

by Ulatekh

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2 Answers

4 votes

(770)(2898.8011666)sin88

Plug in S.A.S. values.

Area

≈

1115358.589

≈

1115358.6

Area≈1115358.589≈1115358.6

Explanation:

Samarth Bhargava answered Nov 12, 2022

by Samarth Bhargava

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4 votes

Answer: 1115358.6

Explanation:

Sneaky answered Nov 16, 2022

by Sneaky

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