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Solid AgCl (Ksp = 1.8 X 10-10) is placed in a beaker of water. After a period of time, the Ag+ concentration is measured and found to be 2.5 X 10-7 M.

a) What is the concentration of Cl-?
b) Has the system reached equilibrium?
c) Will more AgCl dissolve?

User Ekeren
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1 Answer

4 votes

Step-by-step explanation:

a)


k _(sp) = [Ag {}^( + ) ][Cl {}^( - ) ] \\ but \: [Ag {}^( + ) ] = [Cl {}^( - ) ] \\ k _(sp) = [Ag {}^( + ) ] {}^(2) \\ [Ag {}^( + ) ] = \sqrt{k _(sp)} \\ = \sqrt{1.8 * {10}^( - 10) } \\ = 1.34 * {10}^( - 5) mol {dm}^( - 3)

b)

It has not reached equilibrium because the silver concentration is not yet equal to the value of Ksp.

c)

Yes it will dissolve in order to establish the equilibrium.

User Steven Fisher
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