Question

Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods are held 8.0 cm apart by insulating blocks mounted every 1.5 m. If each block can tolerate a maximum tension force of 200 N, what is the maximum allowable current

Answer 1

the maximum allowable current is 7302.967 amperl

Step-by-step explanation:

The computation of the maximum allowable current is shown below;

Force F = mean ÷ 4π 2 I_1 I_2 ÷d × ΔL

200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

I = √200 ÷ √ 3.75 × 10^-6

= 7302.967 amperl

Hence, the maximum allowable current is 7302.967 amperl

Basically we applied the above formula