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On saturday, Mark sold 2 7/8 gallons of lemonade. On the same day, Regan sold 2/3 as much lemonade as Mark. How much lemonade, in gallons, did Regan sell?

On saturday, Mark sold 2 7/8 gallons of lemonade. On the same day, Regan sold 2/3 as-example-1
User Brei
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2 Answers

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2 7/8= 2/3L
Divide both sides by 2/3 and get 4.31 or 4 5/16
User Guy Goldenberg
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Final answer:

Regan sold 1 11/12 gallons of lemonade, which is option B. This is calculated by taking 2/3 of Mark's 2 7/8 gallons.

therefore, option B is correct

Step-by-step explanation:

The student asked how much lemonade, in gallons, Regan sold if she sold 2/3 as much as Mark, who sold 2 7/8 gallons.

First, we convert Mark's sales to an improper fraction: 2 7/8 = (2×8) + 7 = 16 + 7 = 23/8 gallons.

Next, we calculate 2/3 of Mark's sales to find Regan's sales: (2/3) × (23/8) = (2×23) / (3×8) = 46/24. Simplifying this fraction, we get 46/24 = 1 22/24, and further simplifying the fraction part we get 1 11/12.

Therefore, Regan sold 1 11/12 gallons of lemonade, which corresponds to option B. 1 11/12.

the complete Question is given below:

On saturday, Mark sold 2 7/8 gallons of lemonade. On the same day, Regan sold 2/3 as much lemonade as Mark. How much lemonade, in gallons, did Regan sell?

A. 1 5/16

B. 1 11/12

C. 2 7/12

D. 4 5/16

User Emilio Platzer
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