Question

The molarity of 8 grams of an aqueous solution of sodium hydroxide in 2 liters of solute is

Answer 1

Answer: The molarity of 8 grams of an aqueous solution of sodium hydroxide in 2 liters of solute is 0.1 M

Step-by-step explanation:

Given: Mass of solute = 8 g

Volume of solution = 2 L

Molar mass of NaOH is 40 g/mol.

Number of moles of NaOH are calculated as follows.

`No. of moles = (mass)/(molar mass)\\= (8 g)/(40 g/mol)\\= 0.2 mol`

As molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

`Molarity = (no. of moles)/(Volume (in L))\\= (0.2 mol)/(2 L)\\= 0.1 M`

Thus, we can conclude that the molarity of 8 grams of an aqueous solution of sodium hydroxide in 2 liters of solute is 0.1 M.