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The diameter of a circle has endpoints at (3,1) and (11,7) find the radius

User Vanboom
by
3.5k points

2 Answers

1 vote

Answer:

radius = 5 units

Explanation:

The radius r is the distance from the centre to either of the 2 endpoints of the diameter.

Calculate the centre C using the midpoint formula

C = (
(x3+11)/(2),
(1+7)/(2) ) = (
(14)/(2),
(8)/(2) ) = (7, 4 )

Using the distance formula

r =
\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }

with (x₁, y₁ ) = C (7, 4 ) and (x₂, y₂ ) = (11, 7 )

r =
√((11-7)^2+(7-4)^2)

=
√(4^2+3^2)

=
√(16+9)

=
√(25)

= 5

User Nikhil Baliga
by
3.3k points
3 votes

Answer:

the radius of this circle is 5

Step-by-step explanation:

First find the diameter (which is the distance between the two given points). The radius will be half that distance.

Going from (3,1) to (11,7), the x-component increases by 8 (from 3 to 11) and the y-component by 6. The Pythagorean Theorem tells us that the distance between these two points (that is, the hypotenuse) is

d = √(8² + 6²) = √100 = 10. Thus, the radius of this circle is 5.

User Matus Dubrava
by
2.8k points