Answer:
the frequency of the fog horn with a higher pitch is 177.07 Hz
Step-by-step explanation:
Given the data in the question;
time between a minimum and the next maximum in loudness = 0.14 seconds
So,
Time T between the two continuous maximum in loudness will be;
⇒ T = 2 × 0.14 sec
T = 0.28 seconds
Thus, beat frequency
will be;
= 1 / T
we substitute in the value of T
= 1 / 0.28
= 3.5714 Hz
Now, we know that;
=
-

we solve for
=
+

given that; the lower pitch has a frequency of 173.5 Hz
we substitute
= 3.5714 Hz + 173.5 Hz
= 177.07 Hz
Therefore, the frequency of the fog horn with a higher pitch is 177.07 Hz