Question

A 160 g air-track glider is attached to a spring. The glider is pushed in 11.2 cm and released. A student with a stopwatch finds that 14.0 oscillations take 19.0 s . You may want to review (Pages 400 - 402) . For help with math skills, you may want to review: Solving Radical Equations For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Mass on a spring. Part A What is the spring constant

Answer 1

k = 3.41 N/m

Step-by-step explanation:

The time period is given as:

`T = (time\ taken)/(No.\ of\ oscillations) \\\\T = (19\ s)/(14) \\\\T = 1.36\ s`

Another formula for the time period of the spring-mass system is:

`T = 2\pi\sqrt{(m)/(k)} \\\\(1.36\ s)^2 = 4\pi^2(0.16\ kg)/(k)\\\\k = ((4\pi^2)(0.16\ kg))/((1.36\ s)^2)\\\\`

k = 3.41 N/m