9514 1404 393
Answer:
sum = ∑[n=1,5] 4^(n-4)
Explanation:
First of all, you need to be able to describe the n-th term.
Here, we have ...
term #: 1, 2, 3, 4, 5
value: 4^-3, 4^-2, 4^-1, 4^0, 4^1
That is, the exponent of 4 is 4 less than the term number. So, the n-th term is 4^(n-4). The sum of the 5 terms shown is then ...
![\displaystyle sum=\sum_(n=1)^5{4^(n-4)}](https://img.qammunity.org/2022/formulas/mathematics/college/jx49rqo8lvhkpydyttf65sn6aqns6mzfwe.png)