Question

Find the molarity of 4.18 g MgCI2 in 500mL of water

Answer 1

The molarity of MgCl₂ in water is 0.088 mol/L.

Step-by-step explanation:

The molarity of MgCl₂ can be calculated as follows:

`C = (\eta)/(V) = (m)/(MV)`

Where:

C: is the molarity =?

η: is the number of moles of MgCl₂ = m/M

V: is the volume of water = 500 mL = 0.500 L

m: is the mass of MgCl₂ = 4.18 g

M: is the molar mass of MgCl₂ = 95.211 g/mol

Hence, the molarity is:

`C = (m)/(MV) = (4.18 g)/(95.211 g/mol*0.500 L) = 0.088 mol/L`

Therefore, the molarity of MgCl₂ in water is 0.088 mol/L.

I hope it helps you!