Question

Can pls someone help me plsss I need help :(

Answer 1

Answer:
`7,5.66,39^(\circ)`

Explanation:

Given

`IJ=9\\\angle I=51^(\circ)`

from figure, we can write

`\Rightarrow \sin 51^(\circ)=(HJ)/(9)\\\\\Rightarrow HJ=9\sin 51^(\circ)=6.99\approx 7`

`\Rightarrow \cos 51^(\circ)=(HI)/(9)\\\Rightarrow HI=9\cos 51^(\circ)\\\Rightarrow HI=5.66`

In right angle trianle, the sum of the remaining two angles is
`90^(\circ)`

`\therefore 51^(\circ)+\angle J=90^(\circ)\\\Rightarrow \angle J=90^(\circ)-51^(\circ)\\\Rightarrow \angle J=39^(\circ)`