Answer:
3y-x =-6
Explanation:
The equation of a line in point slope form is expressed as;
y-y0 = m(x-x0)
(x0, y0) is the point = (3, -1)
Given the equation 3xs+y = 1
Get the slope
y = -3x + 1
mx = -3x
m = -3
Since the equation needed is perpendicular to the line, the slope will be expressed as;
M = -1/-3
M = 1/3
Substitute and get the equation needed
y-y0 = m(x-x0)
y - (-1) = 1/3(x-3)
y+1 = 1/3(x-3)
3(y+1) = x-3
3y+3 = x-3
3y - x = -3-3
3y-x =-6
This gives the required equation