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Which point is an x-antercept of the quadratic function fix) = (x-8)(x + 9)? (08) 10.-8 (90) (-90)​

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Answer:

(8, 0) and (-9, 0) are the x-intercepts

Explanation:

The x-intercepts are where the graph intersects the x-axis. That means that you need to find the values of x when f(x) = 0.

f(x) = (x - 8)(x + 9) = 0

x = 8 or x = -9

So, (8, 0) and (-9, 0) are the x-intercepts

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