Question

What is the electric field at a distance of 3 cm from 4 mC
of negative charge?
ucharee

Answer 1

The magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.

Step-by-step explanation:

Given;

magnitude of the charge, q = 4 mC = 4 x 10⁻³ C

distance of the charge, r = 3 cm = 0.03 m

The magnitude of the electric field is calculated as follows;

`E = (F)/(q) = (Kq)/(r^2) \\\\`

where;

K is Coulomb's constant, = 9 x 10⁹ Nm²/C²

`E = (Kq)/(r^2)\\\\E = ((9* 10^9)(4 * 10^(-3)))/(0.03^2) \\\\E = 4 * 10^(10) \ N/C`

Therefore, the magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.